Trig stuffs
If sinx = -3/5 and x is in quadrant 3, then tan2x = ? I figured out that cosx is equal to -4/5.... and tanx should be 3/4... but 3/4 times 2 is 6/4 which is not one of the answer choices :/
Ahh, I think I got it! 24/7 right? And it would be positive?
tan(2x) = [2 tan(x)] / [1 - tan^2(x)] and we got tan(x) = 3/4 tan(2x) = [2 (3/4)] / [1 - (3/4)^2] tan(2x) = [3/2] / [1 - 9/16] tan(2x) = [3/2] / [7/16] tan(2x) = 3/2 * 16/7 tan(2x) = 3 * 8/7 tan(2x) = 24/7 Your answer is correct (:
It was marked wrong :( for some reason...
Oops, I forgot to think about positive and negative angles tan x = 3/4 tan^-1 (3/4) = 36.87 It gives us the result in the 1st quadrant, but we know it is in the 3rd so add 180. 180 + 36.87 = 216.87 and that is x, find 2x 2x = 433.74 subtract by 360 to find the coterminal angle :p it gets 73 which is in the first quadrant and it should be positive not sure what we did wrong o.O
@agent0smith @triciaal @imqwerty See where I went wrong? ._.
I checked over it and couldn't see it.
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