(I got the) Power Series Question
Number six
That's what I was going for lol
Well then, props. I wasn't sure.
lol
So my "base" (if thats what its called) is \[\frac{ 1 }{ 1-x }\] If I square it and multiply by two I'll get the expression in my question. Not sure if that has anything to do with it but it seems like a start
Kinda forgotten how to do these, and hungry and need to go to In n Out. I'm not sure if this \[\large \frac{ 2 }{ (1-x)^2 }= 2*\frac{ 1 }{ 1-(2x - x^2) } = ??? ?\]idk, maybe.
no worries. You in cali?
Yep. I was thinkin pizza maybe, but it's been a while since I've been to In N Out, and it is delicious.
dont forget the jungle fries
Animal style fries, yes. I don't know if i have ever ordered regular fries from In N Out.
@ganeshie8 @TheSmartOne any ideas on this?
animal style? enlighten me
I think you're mixing up jungle style for animal style.
they call it jungle style in texas
Ah, I see. It's probably the same thing - cheese, thousand island, onions etc. Example 4 - http://tutorial.math.lamar.edu/Classes/CalcII/PowerSeriesandFunctions.aspx
Oh nvm sorry it's p-terry's that does jungle fries
making me hungry now.
Yeah I'm gonna enjoy those fries and animal style burger!\[\large \frac{ 1 }{ 1-x}=1 + x + x^2 +...+x^n+...\]Use eg. 4's method, find deriv. of above:\[\large \frac{ d }{ dx }\left( \frac{ 1 }{ 1-x} \right)=0 + 1+ 2x +...+nx^{n-1}+...\]
Oh I gotcha. Dont think I would have thought of that without seeing it.
Then don't forget to multiply it by 2.
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