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Simplify: (x^-3-x)/(x^-2-1)
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\[(x^-3 -x)/ (x^-2-1) = \frac{ 1/ x^3 - x }{ 1/x^2 -1 }\]
I would first multiply the top and bottom by x^3
This yields (1-x^4)/ (1-x^3)
Then factor each piece and cancel common factors.
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*oops the bottom would be x-x^3
just to make sure... the answer would be 1+x^2/x
working it
yup!
thanks
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