if f(x)=x^2-1 and g(x)=2x-3, what is the domain of (f*g)(x) A:(negative infinity,positive infinity) B: [-1,positive infinity) C:[-5,positive infinity) D:(positive infinity,negative infinity)
Is it \[(f \circ g)(x)?\]
yeah
Ok that's the same thing as \[f(g(x))\] meaning you can plug in the function g(x) wherever there exists an x in f(x)
Can you try that and see what you get
4x^2-10
\[f(g(x)) = \color\red{(2x-3)}^2-1\] the red is g(x) and black is f(x)
Do you see how I did that?
yea i see do i graph it next?
You could if you like, but we can do it algebraically, do you know how to find the domain for polynomials?
no i usually graph it and try to find the solutions
Well since it's a polynomial only the domain will be all real numbers
hard to graph without the domain....
so its positive infinity to negative infinity
We write it as \[(- \infty, \infty)\]
Think of a number line |dw:1470378191042:dw|
okay
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