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Mathematics 19 Online
OpenStudy (faiqraees):

Why do we need two solutions to solve a 2nd order linear differential equation?

OpenStudy (faiqraees):

@irishboy123

OpenStudy (mrnood):

my input is: Solving this equation essentially involves integrating twice. Each integration involves a 'constant of integration' so you need to known points to calculate those constants. (Any comments welcome - this is not a 'current topic' for me - I may have forgottent the key points...)

OpenStudy (faiqraees):

I am not talking about constants. I am talking about solution Example lets consider a differential equation with equal roots for auxiliary equation. So the reasoning behind why cant we use \[y=Ae^{n_1x}+ Be^{n_2x}\]as its general solution is because since the roots are equal we get a single solution \[y=Ce^{nx}\]. So my question is what's the problem with having one solution. After all it's A SOLUTION.

ganeshie8 (ganeshie8):

Let me ask you a relatively simple and familiar question. How many coordinate axes do you need to locate all the points on the xy plane ?

OpenStudy (faiqraees):

2

ganeshie8 (ganeshie8):

Yes. How many would you be needing if you wanted to locate all the points in 3D ?

OpenStudy (faiqraees):

3

ganeshie8 (ganeshie8):

Could you tell me why/how you think your answers are correct ?

OpenStudy (faiqraees):

Well because in an xy plane, the solution can be made up of both x and y components. The same reasoning can be applied for xyz plane

ganeshie8 (ganeshie8):

Nice, let me ask you another question. Again simpler one, but it takes us in the right direction.

ganeshie8 (ganeshie8):

Can you find the solutions of below ? x + y + z = 1

OpenStudy (faiqraees):

There are infinite solutions

ganeshie8 (ganeshie8):

Yes, but that is a bit vague. I want to know more about the kind of solutions that equation has.

ganeshie8 (ganeshie8):

What geometrical shape does that equation represent ?

OpenStudy (faiqraees):

Well the solution can have imaginary and real roots.

OpenStudy (faiqraees):

A line in a 3D plane

ganeshie8 (ganeshie8):

Assume we're working with reals for now

ganeshie8 (ganeshie8):

Not really. Hasn't your textbook talked about planes yet ?

ganeshie8 (ganeshie8):

If not, its okay. We can discard this idea and think of somehting else :)

OpenStudy (faiqraees):

Oh I am sorry, a plane in a 3D box

ganeshie8 (ganeshie8):

Good. x + y + z = 1 represents a 2D plane. Imagine you're walking on this plane. You would be needing a minimum of 2 different axes in order to reach every point on the plane, right ?

OpenStudy (faiqraees):

I assume we can change the direction of axes in the above example? Like if the plane is tilted, we can tilt our axes. Otherwise for some we would be needing 3

ganeshie8 (ganeshie8):

3 or 4 or 5 also work. But 2 axes will do. Just pick these axes on the plane itself !

OpenStudy (faiqraees):

Yes. I was suggesting the same

ganeshie8 (ganeshie8):

Lets say the unit vectors along those two axes are e1 and e2.

OpenStudy (faiqraees):

Okay

ganeshie8 (ganeshie8):

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