Question

help

Answer 1

Convert the equation into a quadratic equation and then use the given formula to find the roots
\[\large\rm x=\frac{-b±\sqrt{b^2-4ac}}{2a}\]

Answer 2

how do i know which is which?

Answer 3

Have you arranged the equation in quadratic form?

Answer 4

no i am confuse how do u do that

Answer 5

Bring everything on the left side

Answer 6

x^2-12=x

Answer 7

Bring everything. Even x

Answer 8

2x^2-12

Answer 9

x^2 and x are not same variables. Hence they cannot be added

Answer 10

x^2-12-x?

Answer 11

Arrange in the form
ax²+bx+c=0

Answer 12

wait is it already on the form?

Answer 13

No you just have to swap places of -x and -12 and add =0 for the right hand side

Answer 14

oh okay

Answer 15

x^2-x-12=0

Answer 16

\[\large\rm x=\frac{-b±\sqrt{b^2-4ac}}{2a}where~ax^2+bx+c=0~is~the~general~form. \]

Answer 17

so i start plugging in it?

Answer 18

Yes but before that can you confirm me values of a, b and c?

Answer 19

a=x^2 b=-x c=-12

Answer 20

No a =1
b=-1
c=-12
(For a and b we look for coefficient)

Answer 21

oh

Answer 22

wait i am lost i plugged in, it doesnt seem right

Answer 23

how does it look like? Can you show?