Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (flvskidd):

A motorboat takes 5 hours to travel 100mi going upstream. The return trip takes 2 hours going downstream. What is the rate of the boat in still water and what is the rate of the current?

OpenStudy (phi):

is this algebra ?

OpenStudy (flvskidd):

i think

OpenStudy (phi):

Do you know if you are in a boat and the boat just "floats" , it will move downstream at the rate of the current ?

OpenStudy (flvskidd):

Yes I know how to calculate speed I don't know how to calculate the rate of the current

OpenStudy (phi):

Do you know that rate * time = distance ?

OpenStudy (flvskidd):

yes

OpenStudy (phi):

to do the problem, let x= rate of the boat y = rate of the current when the boat goes downstream, it's total rate is x+y any idea what the rate is going upstream ?

OpenStudy (flvskidd):

no

OpenStudy (phi):

if you rowed upstream (instead of in still water), would you go faster or slower compared to still water ?

OpenStudy (flvskidd):

slower

OpenStudy (phi):

if the current carried you backward at a rate of y, and you rowed forward at a rate of x how do you show how fast you are going (compared to still water) want to guess ?

OpenStudy (flvskidd):

the difference of the rates?

OpenStudy (phi):

yes

OpenStudy (phi):

how do you show a difference ?

OpenStudy (flvskidd):

dividing distance by time?

OpenStudy (phi):

difference is shown by subtracting

OpenStudy (flvskidd):

i thought you meant something else, sorry

OpenStudy (phi):

hopefully it make sense: the boat moves upstream at a rate of (x-y) and it goes downstream at a rate of (x+y)

OpenStudy (phi):

A motorboat takes 5 hours to travel 100 miles going upstream. can you write a "rate * time = distance" equation using a rate (going upstream), an unknown time "t" and a distance 100 miles?

OpenStudy (flvskidd):

t x 5 = 100 t x 2 = 100

OpenStudy (phi):

5 hours to travel 100 miles going upstream. time is 5 distance is 100 so it is rate * 5 = 100 but what rate should we use ? remember we are using x= rate of boat and y=rate of the current. how fast does the boat go upstream ?

OpenStudy (flvskidd):

20mph upstream 50mph downstream

OpenStudy (phi):

the boat moves upstream at a rate of (x-y)

OpenStudy (flvskidd):

I forgot what x and y were

OpenStudy (flvskidd):

distance and time?

OpenStudy (phi):

x is how fast the boat moves in still water y is how fast the current moves (x-y) is how fast the boat can go upstream

OpenStudy (flvskidd):

how do you find the current speed

OpenStudy (phi):

we write two equations 5(x-y)= 100 and 2(x+y)= 100 and solve for x and y

OpenStudy (flvskidd):

20 and 50

OpenStudy (flvskidd):

@phi

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!