Can someone help me match the set of vertices with the type of quadrilateral they form? A(2, 0), B(3, 2), C(6, 3), D(5, 1) a parallelogram with nonperpendicular adjacent sides A(3, 3), B(3, 6), C(7, 6), D(7, 3) a rectangle with noncongruent adjacent sides A(-5, -3), B(-4, -1), C(-1, -1), D(0, -3) a square A(2, -2), B(3, 0), C(4, -2), D(3, -4) a rhombus with nonperpendicular adjacent sides A(3, 3), B(2, 5), C(4, 6), D(5, 4)
Try taking one of the sets of points and graphing them... See what you get and see which of the explanations of figures matches the set of points.
As an example consider the first set of points: A(2, 0), B(3, 2), C(6, 3), D(5, 1). When graphed it looks like this:
In this case, thanks to @mathmate, it is a Rhombus.
It is not a rhombus because not all sides are congruent.
Right, it's a parallelogram. I was looking at it in small scale and thought "it looks like a rhombus".
If you prefer to work with the coordinates, you can do so using three simple tests, 1. to test if it is a parallelgram: check if \(x_a+x_c=x_b+x_d\) 2. to test if adjacent sides are equal (for squares and rhombuses) check if \((x_b−x_a)^2+(y_b−y_a)^2=(x_c−x_b)^2+(y_c−y_b)^2\) Note: you don't even need to square the numbers if the numbers are like \((−3)^2+4^2\) and \(4^2+3^2\) because we know that after squaring, the sums will be identical. 3. to test if adjacent sides are perpendicular (for squares, rectangles) check if \(\frac{yb−ya}{xb−xa}\times \frac{yc−yb}{xc−xb}=−1\) Once you have the information, you can determine which type of quadrilateral it is, among parallelogram, rhombus, square and rectangles. For examples and proofs, see: http://mathm8.altervista.org/geometry/index.html
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