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Mathematics 10 Online
OpenStudy (diogop110):

What's the oxidation number in this complex: [Cu(NH3)4]2+ ? How did you do?

OpenStudy (diogop110):

Oxidation number of Cu

OpenStudy (zpupster):

http://apbrwww5.apsu.edu/robertsonr/chem1110-20/oxnumber.pdf from copper is +1 or +2 n=-3 * 4 = -12 h= 1 then *3=3 then*4 = 12 NH3 is neutrally charged

OpenStudy (diogop110):

thank you @zpupster

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