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OpenStudy (diogop110):
What's the oxidation number in this complex: [Cu(NH3)4]2+ ? How did you do?
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OpenStudy (diogop110):
Oxidation number of Cu
OpenStudy (zpupster):
http://apbrwww5.apsu.edu/robertsonr/chem1110-20/oxnumber.pdf from copper is +1 or +2 n=-3 * 4 = -12 h= 1 then *3=3 then*4 = 12 NH3 is neutrally charged
OpenStudy (diogop110):
thank you @zpupster
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