At a pressure 44 kPa, the gas in a cylinder has a volume of 14 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 9 liters, what is the new pressure? kPa

Question

At a pressure 44 kPa, the gas in a cylinder has a volume of 14 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 9 liters, what is the new pressure?  kPa

thesmartone · Answer

Boyle's law.

Ever heard of it?

tamika · Answer

no

tamika · Answer

can u help me?

thesmartone · Answer

Boyle's law states that the product of pressure and volume will remain a constant as long as the temprature is constant.

So basically, the formula for Boyle's law is

$\Large P_1V_1 = P_2V_2$

And we've been given everything except for $\Large P_2$ which is what we're finding. :)

tamika · Answer

what does p stand for?

thesmartone · Answer

Pressure
V stands for volume

thesmartone · Answer

$\Large P_1 = 44~kPa\\Large V_1 = 14~liters\\Large V_2 = 9~liters\\Large P_2 = ??$

tamika · Answer

67?

thesmartone · Answer

How did you get 67? Can you show your work? :)

tamika · Answer

I added

thesmartone · Answer

If you look at the equation, you will see we are multiplying.

$\Large P_1V_1 = P_2V_2$

sweetburger · Answer

The pressure and volume of a gas kept at a constant temperature are inversely proportional to each other.