Question

simplify

Answer 1

\[\sqrt{x} \times \sqrt[3]{x} \times x^\frac{ 1 }{ 6 }\]

Answer 2

Another helper shared with you a set of rules of exponents. Did you write down those rules for later reference?

Hint: Rewrite the first 2 multiplicands with fractional exponents, so that all 3 factors have the same style as the 3rd multiplicand has now.

Answer 3

would that make it \[x^\frac{ 1 }{ 2 } \times x^\frac{ 1 }{ 3 } \times x^\frac{ 1 }{ 6 }\]

Answer 4

@mathmale

Answer 5

Yes, indeed. Very good. Now, what is the rule for calculating x^a * x^b * x*c?

Answer 6

Hint: This rule involves addition.

Answer 7

you add the exponents but have to find the common denominator right?

Answer 8

does it just = 1?

Answer 9

@mathmale

Answer 10

bc i got \[x^\frac{ 3 }{ 6 } \times x^\frac{ 2 }{ 6 } \times x^\frac{ 1 }{ 6 }\] and then i added them all and got \[x^\frac{ 6 }{ 6 }\] which equals x

Answer 11

or do i square root it?

Answer 12

You practically have the answer already.

Your \[x ^{\frac{ 6 }{ 6 }}=x^1=x\]

Answer 13

So, yes, the sum of these 3 exponents is 1. But 1 alone is not your answer; the complete answer is x^1 = x.

Answer 14

sweet okay i get it

Answer 15

thanks for helping me out

Answer 16

My pleasure. Later.