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Chemistry 18 Online
OpenStudy (kittiwitti1):

Answer what you can. 3. Which of the following statements is/are correct? i. An object hanging motionless on a spring is in a static equilibrium ii. In a dynamic equilibrium, the reversible changes occur continuously, even though there is no appearance of change iii. The amounts of substances present in a system at equilibrium are equal a. i only b. ii only c. iii only d. i and ii e. ii and iii (i) correct (?) (ii) correct as both sides of the equation are occuring simultaneously in equal order (iii) correct as the amounts are equally proportionate ACTUAL ANSWER: (i) is wrong but the other two are correct ?

OpenStudy (kittiwitti1):

8. A molecular collision is sufficiently energetic to cause a reaction, yet no reaction occurs. Which of the following is the least likely explanation?   a.  The proton–proton interaction is too large   b.  The molecules have poor orientation   c.  One of the molecules is not moving too slowly.   d.  One or both the molecules does not have enough energy.   e.  All of the above could be an explanation. \(\color{steelblue}{\text{My answer}}\) E. \(\color{red}{\text{Actual answer}}\) A.

OpenStudy (frostbite):

For 8 the answer is straight forward: When you are looking at a chemical reaction proton-proton interactions are 100% irrelevant. In chemistry it is usually the electron repulsion and attraction that is relevant weather or not a chemical reaction can occur. You can remember it like this: proton-proton interactions are relevant when you want to change the nuclei.

OpenStudy (kittiwitti1):

OH. I probably misread as "most likely" my bad!

OpenStudy (kittiwitti1):

do you know about the other one though?

OpenStudy (frostbite):

I am still thinking about it. Usually not working with static equilibria, so looking up some definitions.

OpenStudy (kittiwitti1):

also I think (c) is a typo, yes?

OpenStudy (kittiwitti1):

for 8. "is not moving too slowly" idk

OpenStudy (frostbite):

Might be a typo, it could be a reference to it does not possess enough kinetic energy, at least that is what got to my mind when reading it.

OpenStudy (kittiwitti1):

hmm. maybe ok and this one? we can skip 3 if it's too confusing 14. If a reaction is carried out in an aqueous solution, which of the following changes would not affect the rate of the reaction?   a.  Increasing the temperature   b.  Changing the concentration of reactants   c.  Increasing the size of the reaction vessel   d.  Adding a catalyst   e.  More than one would not affect the rate of the reaction so far my answer (♣) and actual answer (♦): ♣ A ♦ C

OpenStudy (kittiwitti1):

I know A is wrong because temperature DOES increase rate, but why is C right?

OpenStudy (frostbite):

I don't know if the answer is as simple as: if you increase the size of the reaction vessel you lower the concentration of the reactants due to the reciprocal relationship between concentration and volume.

OpenStudy (frostbite):

And you know from kinetics the rate depends on the concentration (in some cases)

OpenStudy (kittiwitti1):

Maybe because the equilibrium adjusts to the new size and is still proportional?

OpenStudy (kittiwitti1):

I mean, that sounds most reasonable

OpenStudy (frostbite):

Except the equilibrium constant does not depend on the volume.

OpenStudy (kittiwitti1):

I didn't mean equilibrium constant though.

OpenStudy (frostbite):

Yeah sorry also a bad argument. I don't think we can use equilibrium considerations here cause they are usually rapid. I think the best argument is due to concentration. Any non-zero order reaction would decrease in rate by increasing the volume.

OpenStudy (kittiwitti1):

Bad argument for what? I'm trying to prove that (c) "increasing the vessel size" would not affect rate

OpenStudy (kittiwitti1):

You kinda lost me... sorry

OpenStudy (frostbite):

Oh not affect the rate... sorry I thought it would be decrease the rate... cause all the other reasons increase the rate.

OpenStudy (kittiwitti1):

So does the volume change affect rate? o_o

OpenStudy (frostbite):

Theoretically I would guess yes. but the effect would be low, so no. :P I am a little unsure.

OpenStudy (kittiwitti1):

So not as much as the others. Or not noticeable. That suits me just fine lol

OpenStudy (kittiwitti1):

24. If the position of equilibrium shifts to the left, what will happen?   a.  The concentration of products will increase   b.  The concentration of reactants will increase   c.  The temperature will rise   d.  The temperature will decrease   e.  The concentrations of both products and reactants will increase the answer is B but I'm not sure why.

OpenStudy (kittiwitti1):

if it shifts left... does that mean there are less products now?

OpenStudy (frostbite):

Yes. So I think you should imagine their question like this: |dw:1470907413067:dw|

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