Question

Write the equation of a line with a slope of 4 and a y-intercept of −3.

4x + y = −3
4x – y = −3
y = −3x + 4
y = 4x − 3

Answer 1

The slope is the "rate of increase".

That means: for \(x=0\), the corresponding value of \(y\) is the intercept.

Which of your equations verifies : "if x=0, then y=-3" ? (two possibilities)

Answer 2

4x + y = -3

Answer 3

good, there's another one: y = 4x - 3.

Answer 4

So it's D?

Answer 5

That's two candidates.

Among those two, which one has a slope equal to 4 ?

To find the slope based on an equation, always isolate the \(y\), then read the factor of \(x\).

Example: \(3x+2y=1\) becomes \(y = \frac32x + \frac12\). Factor of \{x\) is \(\frac32\), it is the slope.

What about the two candidates?

Answer 6

Oh well, yes

Answer 7

Ohhh I see

Answer 8

(oops. I meant: \(y = -\frac32x + 1\)... )

Answer 9

So the answer is still the same?

Answer 10

that was just my example.. \(3x+2y=1\) us equivalnet to \(y=-\frac32x+1\) and the slope is \(-\frac32\).

For your question,
-slope of line with equation 4x + y = −3 is \(-4\).
-slope of line with equation y = 4x-3 is .. \(4\) (nothing to do here). -> answer D)

Answer 11

(aaargh \(y = -\frac32x + \frac12\) but that doesn't matter!! ;))

Answer 12

Oh thanks. Can u help me with 2 more?

Answer 13

2 like this one sure

Answer 14

and I'm not alone :'>

Answer 15

What you mean?

Answer 16

There are other people who are able to answer. Please post your question

Answer 17

Ok

Answer 18

Close this question and post a new one please :-)

Answer 19

ok

Answer 20

Thanks