- Setup linear equations from word problem.
A paint manufacturer produces 2 paints of different colour – red and blue. It takes 1 hour to mix a vat of paint regardless of colour. There are however only 40 hours available per week for mixing. The cost of producing a vat of red paint is €200 whilst the cost of producing a vat of blue paint is €100. Production costs are limited to €6000. The profit (which the manufacturer wishes to maximise) made on each vat of red paint sold is €50 and on each vat of blue paint sold it is €40.
I see the maximisation function is 50x + 40y. But the constraints? 200x + ? = 6000? 100x + ? = 6000?
@agent0smith Literally my last Q to ask on here!
Thought about 200 R + 100 B <=6000 production cost? R + B <= 40 production time?
x+y <= 40?
i'm using descriptive variable names R for no of red tins he makes in week B for Blue
Thats not correct unfortunately, used Wolfram to check.
What do you mean you used WA to check that it's not correct?
http://www.wolframalpha.com/input/?i=200+R+%2B+100+B+%3C%3D6000,+R+%2B+B+%3C%3D+40,+R+%3E%3D+0,+B+%3E%3D+0 (20, 20) gives a max value for 50R + 40B of 1800.
i drew it, because MW hates me, and I got the same. must be wrong.
The one he posted yesterday had a different answer, too. I'm not seeing how, unless the book's answers are unreliable.
Agent you here man? :)
Yes
The solution offered in my book says: Ans: z = 18003; Red = 20, Blue = 20 You think that 3 is a typo?
LOL how would a 3 even get in there when the profit function is 50x + 40y
So would the constraints be: 200x + 100y <=6000 production cost? x + y <= 40 production time?
Don't forget x >= 0 y >= 0
Yeah, that's the correct solution then.
Constraints*
Yeah, your book seems like it probably had some poor editing.
Sucks because that can really set you off!
Oh yeah, it's frustrating.
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