Question

Given the arithmetic sequence an = 3 + 2(n − 1), what is the domain for n?

Answer 1

@retirEEd

Answer 2

@kidrah69

Answer 3

is it all integers greater than or equal to 1

Answer 4

Why can't n be a negative or zero?

Answer 5

cause domains for sequences are always positive numbers

Answer 6

right?

Answer 7

I really don't know that to be true, so I will have to go to Google that statement.

Answer 8

is this answer correct?

Answer 9

i googled it it is true

Answer 10

according to Google...

• The domain of a sequence consists of the counting numbers 1, 2, 3, 4, ...
and the range consists of the terms of the sequence.

Your statement is correct, so I think you are right.

Answer 11

Thanks.
Can you check the other attachment i sent? i know the sum is 168 I'm just stuck

Answer 12

I think the answer is going to be either c or d, not b let check again

Answer 13

well the sum is 168 i know that, so then it must be d huh?

Answer 14

if it is 168 then it must be d since when i=1 a1 = 42

Answer 15

it is last option

Answer 16

\[a _{n}=ar ^{n-1}\]
\[\sum_{i=1}^{\infty}a _{i}=\sum_{i=1}^{\infty}42\left( \frac{ 3 }{ 4 } \right)^{i-1}=\frac{ 42 }{ 1-\frac{ 3 }{ 4 } }=?\]

Answer 17

for first
sequence is first term,second term, third term,...
so n=1,2,3,...

Answer 18

for second
\[common~ratio~r=\frac{ 3 }{ 4 }<1\]
\[s _{\infty}=\frac{ a }{ 1-r }\]