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Mathematics 14 Online
OpenStudy (shaleiah):

Please help me

OpenStudy (shaleiah):

OpenStudy (shaleiah):

@DullJackel09

OpenStudy (shaleiah):

@Abmon98

OpenStudy (shaleiah):

@karim728

OpenStudy (agent0smith):

http://openstudy.com/users/shaleiah#/updates/57ad29f2e4b0b5aaebb0b8cc All you need to do is identify the points, as I was trying to get you to do.

OpenStudy (shaleiah):

the first point is 0

OpenStudy (agent0smith):

Points are two values, and x and a y. Given as (x, y). For example, one of the points is (2, 150).

OpenStudy (shaleiah):

Alright

OpenStudy (shaleiah):

First point- (0,0)

OpenStudy (agent0smith):

And the last point?

OpenStudy (shaleiah):

(8, 350)

OpenStudy (agent0smith):

Now find the slope between those two points.

OpenStudy (agent0smith):

By showing work, that is.

OpenStudy (shaleiah):

\[\frac{ f(b)-f(a) }{ b-a }=\frac{ 350-8 }{ 350-8 }=1\]

OpenStudy (agent0smith):

Your numbers are all plugged in wrong. Points are (0, 0) (8, 350) On the numerator, should be the y values. On the denominator should be the x values. If you know how to find the slope of a line (the slope formula) you are doing the EXACT same thing here.

OpenStudy (agent0smith):

\[\large \frac{ y_2 - y_1 }{ x_2 - x_1 }\]

OpenStudy (shaleiah):

-175/4

OpenStudy (agent0smith):

Show work, because no.

OpenStudy (shaleiah):

\[\frac{ 350-0 }{ 0-8 }\] =-175/4

OpenStudy (agent0smith):

Close but not quite. (0, 0) is \((x_1, y_1)\) (8, 350) is \((x_2, y_2)\)

OpenStudy (shaleiah):

\[\frac{ 350-0 }{ 8-0 }=43.75\]

OpenStudy (agent0smith):

Now repeat the same method for the rest. First identify the points, then find the slope between them.

OpenStudy (shaleiah):

(2,150) (4,240)

OpenStudy (agent0smith):

I think it's probably 225 not 240

OpenStudy (shaleiah):

are you sure?

OpenStudy (agent0smith):

It's in the middle between 200 and 250, so yes.

OpenStudy (agent0smith):

Now find the slope

zarkam21 (zarkam21):

Go to www.mathway.com It helps alot just put in the value :)))

OpenStudy (shaleiah):

can't... that's cheating.

OpenStudy (shaleiah):

\[\frac{ 225-150 }{ 2-4 }=-37.5\]

OpenStudy (mathmale):

Why have you input 2-4 instead of 4-2? Your formula is fine; the order in which you've entered your data is not.

OpenStudy (agent0smith):

You made the same mistake as earlier... gotta pay attention to your mistakes and learn from them.

OpenStudy (mathmale):

Note the order of appearance of the variables in the 'average rate of change" formula:\[ave.r.of.change=\frac{ f(b)-f(a) }{ b-a }\]

OpenStudy (shaleiah):

b. 37.5

OpenStudy (agent0smith):

Good, keep going. You should be able to do them all now.

OpenStudy (shaleiah):

(4,225) (5,300)

OpenStudy (agent0smith):

Yep

OpenStudy (shaleiah):

\[\frac{ 300-225 }{ 5-4 }=75\]

OpenStudy (agent0smith):

Yep

OpenStudy (shaleiah):

(5,300) (6,300)

OpenStudy (agent0smith):

Yep

OpenStudy (shaleiah):

\[\frac{ 300-300 }{ 6-5 }=0\]

OpenStudy (agent0smith):

Yep

OpenStudy (shaleiah):

(8,350) (6,300)

OpenStudy (shaleiah):

\[\frac{ 350-300 }{ 8-6 }=25\]

OpenStudy (agent0smith):

Yep

OpenStudy (shaleiah):

@mathmale what could I say for C ?

OpenStudy (agent0smith):

They were driving at diff. speeds

OpenStudy (shaleiah):

Alright, for D: No, the rate of change isn't constant over the entire trip.

OpenStudy (agent0smith):

Yes

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