Question

Part A)

5x+3(x−5)=6x+2x−15

Simplify both sides of the equation.

5x+3(x−5)=6x+2x−15

Simplify:

5x+3(x−5)=6x+2x−15

5x+(3)(x)+(3)(−5)=6x+2x+−15(Distribute)

5x+3x+−15=6x+2x+−15

(5x+3x)+(−15)=(6x+2x)+(−15)(Combine Like Terms)

8x+−15=8x+−15

8x−15=8x−15

Subtract 8x from both sides.

8x−15−8x=8x−15−8x

−15=−15

Add 15 to both sides.

−15+15=−15+15

0=0

Only one solution.

Part B)

I used distributive property.

Answer 1

anyone? i need help

Answer 2

@mathmale @mathmate

Answer 3

can you tell the answer then explain??

Answer 4

That first part of 0=0 means there are an infinite number of solutions.

Answer 5

one solution would be something like x=4, while no solutions would be something like 0=10

Answer 6

As for part B what is the question?

Answer 7

How many packets of chocolate wafers and vanilla wafers did they buy? Explain how you got the answer and why you selected a particular method to get the answer.

Answer 8

there you go

Answer 9

Um what was the initial problem I guess then, all I see is the algebraic equation.

Answer 10

here ill give you the whole question

Answer 11

Josh and his friends bought vanilla wafers for $4 per packet and chocolate wafers for $1 per packet at a carnival. They spent a total of $45 to buy a total of 27 packets of wafers of the two varieties.

Part A: Write a system of equations that can be solved to find the number of packets of vanilla wafers and the number of packets of chocolate wafers that Josh and his friends bought at the carnival. Define the variables used in the equations.

Part B: How many packets of chocolate wafers and vanilla wafers did they buy? Explain how you got the answer and why you selected a particular method to get the answer.

Answer 12

Ah ok so you would have two equation lets call V the number of vanilla wafers and C the number of chocolate wafer

Answer 13

whalenjacob is typing...

Answer 14

ok

Answer 15

One equation for the total spent, and another for the total number of items.

Answer 16

ok

Answer 17

So for the number of items V+C=27

Answer 18

Since they bought a total of 27 items

Answer 19

alright

Answer 20

For money spent 4V+1C=45

Answer 21

ok

Answer 22

So now we use either substitution or elimination method for two equations.

Answer 23

Do you have a preference

Answer 24

not really anyone you choose im fine with

Answer 25

Ok rearranging the first equation we get V=27-C

Answer 26

yup[

Answer 27

Then plugging into the second we have 4(27-C)+1C=45

Answer 28

So now we can solve for C

Answer 29

ok

Answer 30

So using the distributive property that become 4*27-4C+1C=45

Answer 31

ok i got it

Answer 32

Ok so what do you get for C

Answer 33

21?

Answer 34

Thats what I get

Answer 35

So finally since you know there are a total of 27 items the remaining are vanilla.

Answer 36

i thought it was 21

Answer 37

Right 21 Chocolate and the remainder of the 27 candies are vanilla.

Answer 38

oh duh im sorry

Answer 39

So 21 Chocolate and 6 Vanilla

Answer 40

And that would be one way of solving the problem.

Answer 41

ok ill be right back stay and ima be right back