Find the derivative of f(x) = -7/x at x = -3.
I got 7/3 as the answer but it said its wrong
It may help you to re-write f(x) = -7/x as \[f(x)=-7x ^{-1}.\]
ok so, 1/-7x?
Focus on \[x ^{-1}\]. What's the derivative of \[x ^{-1}?\]
Hint: Use the Power Rule for Differentation.
\[\frac{ d }{ dx }x^n=nx ^{n-1}\]
So, \[\frac{ d }{ dx }x ^{-1}=?\]
never saw that before, online class skipped over it completely Let me think
What is n in\[\frac{ d }{ dx }x ^{-1}~?\]
-1
so we get -1x^-2?
Again, this is the Power Rule for Differentiation. Yes, n=-1. Now, please find\[\frac{ d }{ dx }x ^{-1}\]
Yes, you have that correct.
But remember that your original problem began with "-7." You must keep that "-7". So, what is your final result?
-7x^-2?
\[\frac{ d }{ dx }[-7x ^{-1}]=?\]
You have -7 as your coefficient, and your n is = -1. What is (-7)(-1)?
oops you're right, its +7x
Your +7 is correct, but your "x" is not.
\[\frac{ d }{ dx }[-7x ^{-1}]=?\]
You must use the "Power Rule for Differentiation."
+7x^-2
Yes, basically that's correct. I'd prefer that you write 7x^(-2), so that it is clear to the reader that your exponent is negative. Now, let x=-3 in your final result.
Be certain to enclose your -3 inside parentheses: 7(-3)^(-2)=?
Note that you MUST do the exponentiation first here, and only then do the multiplication.
7*(-3)^(-2) = 7 * 1/9 = 7/9
beautiful.
thank you very much
my pleasure!
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