Length of loop
the question is as attached
Question from Kangaroo competition?
and my working are attached too now the answer is supposed to be \[4\sqrt{3}\] but i got something that's close but not exactly it
@FaiqRaees no, sorry
i mean, when you put it in decimals, my answer and the right answer are close but it's not really that so i tried to look at my calculations but everything looks fine to me? was my method wrong?
Youre using the formula for a polar arclength, but your coordinates are Cartesian arent they?
im not sure, thats just a hunch.
oh... probably... >.<
Your formula is fine.
Can you explain me below step ? |dw:1471114491620:dw|
@ganeshie8 OOOOHHHH!! bollocks! i ate away some of the powers, didn't i??? wait let me try and correct that pronto!!!
She I suppose made an illogical substitution \(t=t^2 \)
Haha yeah. Looks you should get below as the integrand \[\sqrt{(t^2+1)^2}\]
@ganeshie8 i am so sorry!! it works fine now *facepalm*
That's okay :) Also, you may check your work with wolfram http://www.wolframalpha.com/input/?i=Integrate%5Bsqrt((2t)%5E2+%2B+(1-t%5E2)%5E2),+%7Bt,+-sqrt(3),sqrt(3)%7D%5D
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