Question

Can anyone help me in this

Answer 1

With what?

Answer 2

yes sure than you write here your question we can try help you

Answer 3

\[\cos ^{2}\alpha+\cos ^{2}\beta+\cos ^{2}\gamma=1\]

How can the above expression be expressed as

Answer 4

<< ... expressed as >> ... as what ?

Answer 5

in a different form ? using what ? in function of what ?

Answer 6

???

Answer 7

hope you know that sin^2 ß + cos^2 ß = 1

yes ?

Answer 8

using this you can rewriting this your given equation in the form of

cos^2 alpha = 1 -sin^2 alpha for example so than you need rewrite it using sinus

Answer 9

@TheSmartOne do you understand this question really ?

Answer 10

no, seems incomplete

Answer 11

uhuh

Answer 12

i m trying attach

Answer 13

its just not happening

Answer 14

network seems slow

Answer 15

so there are
1
= ----------------------------
sqrt( (h/a)^2 +(k/b)^2 +(l/c)^2 )

ok. but what is in front of this ,,equal" sign ?

Answer 16

\[=\frac{ 1 }{ \sqrt{(\frac{ h }{ a })^{2}+(\frac{ k }{ b})^{2}+(\frac{ l }{ c })^{2^{}}} }\]

Answer 17

That's what is written there

Answer 18

yes - ok. but in front of this fraction what wan being ?

Answer 19

its an '=' sign

Answer 20

yes ok. and in front of this equal sign need being there anything or not ?

Answer 21

I doubt that the '=' sign is relevant

Answer 22

cos2α+cos2β+cos2γ=1

this wan being in front of this equal sign without 1 so just the left part of this equation ?

Answer 23

I think this person means express the first equation in terms of that expression

Answer 24

yes i think it same too - but the asker go away - not is here online

Answer 25

and we need to know what are from there h,k and l so a,b, and c and so from this above first wrote equation this alpha,beta and gamma what mean these exactly ?

Answer 26

d= the expression in attachment

Answer 27

@jhonyy9 Sorry there was network error when i uploaded.
can u help me now?