Find f'(a)
\[f(t) = \frac{ 2t+1 }{ t+3 }\]
first find f'(t) use the Quotient rule.
I haven't learned any of the rules yet, my teacher said to use the definition of the derivative.. she said we had to show all of our work to get credit :3
I haven't done any with fractions like this yet though...
http://archives.math.utk.edu/visual.calculus/2/definition.12/eq1.gif \[\Large f'(x) = \lim_{h \rightarrow 0} \frac {\frac{ 2(t+h)+1 }{ (t+h)+3 } - \frac{ 2t+1 }{ t+3 } }{ h }\]Now we gotta simplify some fractions and get common denoms.
Perfect, thank you! I can handle it from here. Just couldn't figure out how to set it up...
Okay, let me know if you get stuck, but it's not too bad from there, just getting common denoms
I keep messing up :/ \[\frac{ (t+3)(2t+2h+1)-(2t+1)(t+h+3) }{ h(t+3)(t+h+3) }\] Does this look right so far?
Never mind, I just got it! Ahh :D Long problems.
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