find the inverse
\[f(x)=\frac{ x^2 }{ 3 }\]
Basic outline: step 1) replace f(x) with y step 2) swap x and y step 3) solve for y
You'll have to restrict the domain so that the function is one-to-one. Otherwise, the inverse will not be a function.
One restriction you could make is \(\Large x \ge 0\)
okay so what do I do after I restrict it
follow that outline I posted
\[\Large f(x)=\frac{ x^2 }{ 3 }\] \[\Large y=\frac{ x^2 }{ 3 }\] \[\Large x=\frac{ y^2 }{ 3 }\] solve for y. Keep in mind that \(\Large x \ge 0\)
Also, when x and y swap, everything about them swaps as well So if \(\Large x \ge 0\) in the original, then \(\Large y \ge 0\) for the inverse
o should I square root the two sides?
before that, multiply both sides by 3 isolate the y^2 first, then isolate y itself
\[\sqrt{3x}=y\]
now idk what to do
so the inverse is \[\Large f^{-1}(x) = \sqrt{3x}\] where \(\Large x \ge 0\)
so that's the answer?
like there isn't anything else to do to it?
what do mean "anything else to do to it" ? once you get to sqrt(3x), you're done
okay
thanks for helping me again ;0
glad to be of help
Join our real-time social learning platform and learn together with your friends!