Question

Find the perimeter of a triangle with side lengths (6x+2) in, (x-12) in, and (3x+15) in.

Answer 1

perimeter of a triangle \[\large \rm P=x+y+z\]

Answer 2

How do ! add them together though

Answer 3

combine like terms
add the coefficients of identical variables

Answer 4

for example
2x+7x = (2+7)x =9x

Answer 5

Ok so after adding the like terms I get 10x and 5

Answer 6

10x and 5
is it +5 or -5 ?

Answer 7

+5?

Answer 8

yes right good!

Answer 9

don't forget the unit !

Answer 10

Ok so how do i right the answer (10x+5) or (10x-5)

Answer 11

I write the answer* excuse me

Answer 12

did you get -5 or +5 ?? :=))

Answer 13

OHHHHHH ok thanks a lot

Answer 14

\[\huge\rm P=(6x+2)in+(x-12)in+(3x+15)in\]
there are + signs so you can remove the parentheses \[\large\rm P=6x+2~in+x-12~in+3x+15~in\]
combine like terms

Answer 15

so how would you write your final answer ?

Answer 16

(10x+5)

Answer 17

Am I correct

Answer 18

\[\large\rm P=(6x +2 )\color{red}{in}+(x-12)\color{Red}{in} +(3x+15)\color{red}{in}\]
don't forget the unit..
\[\large\rm P=(6x +2 +x-12+3x+15) \color{Red}{in}\]

Answer 19

yes that's correct 10x+5 `in`

Answer 20

10x+5in

Answer 21

Thanks

Answer 22

ye or you can write it as (10x+5)in

Answer 23

for example if the sides are 4 m , 5m , 6m
then the perimeter would be P=4m+5m+6m=(4+5+6)m = 15m
the unit is important
it workz the same way like `like terms`

Answer 24

yw