You can approximate e by substituting large values for n into the expression ________.
A. (1-n)^1/n
B.(1+1/n)^n
C. (1+n)^1/n
D.(1-1/n)^n

Question

You can approximate e by substituting large values for n into the expression ________.
A. (1-n)^1/n
B.(1+1/n)^n
C. (1+n)^1/n
D.(1-1/n)^n

zzr0ck3r · Answer

google

evoker · Answer

I would recommend looking at the wiki for e

snowflakelove15 · Answer

I did I couldn't find anything

evoker · Answer

It's in the first couple sentences on the Wikipedia entry

zzr0ck3r · Answer

B

zzr0ck3r · Answer

lol

jim_thompson5910 · Answer

You can plug in large numbers into n (like n = 1000) and see which get you close to e = 2.71828182846...

snowflakelove15 · Answer

Thank you both of you, B was correct!

zzr0ck3r · Answer

hint: $e^x=\lim_{n\rightarrow \infty}(1+\frac{x}{n})^n$

jim_thompson5910 · Answer

Yes it's B since

(1+1/n)^n = (1+1/1000)^1000 = 2.7169239322356

which is fairly close. Just off at the 3rd decimal digit. Use larger values of n to get closer

zzr0ck3r · Answer

https://en.wikipedia.org/wiki/List_of_representations_of_e This has a bunch of them