Question

You can approximate e by substituting large values for n into the expression ________.
A. (1-n)^1/n
B.(1+1/n)^n
C. (1+n)^1/n
D.(1-1/n)^n

Answer 1

google

Answer 2

I would recommend looking at the wiki for e

Answer 3

I did I couldn't find anything

Answer 4

It's in the first couple sentences on the Wikipedia entry

Answer 5

B

Answer 6

lol

Answer 7

You can plug in large numbers into n (like n = 1000) and see which get you close to e = 2.71828182846...

Answer 8

Thank you both of you, B was correct!

Answer 9

hint: \(e^x=\lim_{n\rightarrow \infty}(1+\frac{x}{n})^n\)

Answer 10

Yes it's B since

(1+1/n)^n = (1+1/1000)^1000 = 2.7169239322356

which is fairly close. Just off at the 3rd decimal digit. Use larger values of n to get closer

Answer 11

https://en.wikipedia.org/wiki/List_of_representations_of_e

This has a bunch of them