Question

Relatively simple graph problem that I don't get that well, I'm a little rusty haha. http://imgur.com/a/4Wg6v

Answer 1

@jim_thompson5910 @pooja195 @agent0smith @sammixboo @ShadowLegendX @sweetburger @Anaise @kidrah69 @quickstudent @Donblue22 @Aleah54 @Evoker

Answer 2

I know the answer is about 230, but I can't deduce why.

Answer 3

Distance = area under a speed-time graph.

Answer 4

Draw triangles etc to approximate the area, or just count the unit squares (notice each unit on the x axis is 1/3 of an hour, each unit on the y is 10 km/h).

Answer 5

Have you studied calculus yet?
When "integration" is introduced, you learn how to approximate areas under curves from one x value to another.
You could draw vertical lines through every unit marked on the x-axis, e. g., at 6, 6 1/3, 6 2/3, 7, 7 1/3, etc. As agent0smith suggests, you could then estimate the area of each triangle or trapezoid, and then add up all of the areas of all of the trapezoids to get the approx total area. For more info, please draw vertical lines through 6 1/3 and 6 2/3, estimate the short and long sides of the resulting trapezoids, and then estimate the two areas you delignate in this manner. Share your work if you're not sure; someone will reinforce your efforts.

Answer 6

If you have already learned and used the trapezoidal rule, try using that to estimate the total area under this curve. Questions?

Answer 7

Bear: Please respond.

Answer 8

@agent0smith @mathmale I tried what you guys said out and it worked! I got 204, which I guess is close enought to 230. Thanks a lot for the help!

Answer 9

Well it's an estimate, so it depends how inaccurate you were (or they were).

Answer 10

It was probably me, my triangles were a bit funky haha