Question

College Algebra/Alg. 2 Review- operations with rational expressions (polynomials)

Answer 1

\[\frac{ (-3mn)^2*64(m^2n^3)^2 }{ 16m^2n^4(mn^2)^3 } * \frac{ (3m^2n^3)^2 }{ 24(m^2n^2)^4 }\]

Answer 2

The answer is 27/2mn^7 but I don't know how to get there.

Answer 3

first use these properties to simplify

\(\Large (a^b)^c = a^{bc}\)

\(\Large a^b\times a^c = a^{b+c}\)

Answer 4

\[\frac{ 9m^2n^2*64m^6n^3*9m^4n^6 }{ 16m^2n^4*m^3n^6*24m^8n^8 }\]

Answer 5

\[\frac{ 81m^6n^8*64m^6n^3 }{ (16m^5(n^10))*24m^8n^8 }\]

Answer 6

now I have \[\frac{ 27*4m }{ n^7 }\]

Answer 7

you made a mistake right here
http://prntscr.com/c6a6en

it should be

(m^2n^3)^2 = m^4n^6

Answer 8

\[\frac{ 9m^2n^2*64m^4n^6*9m^4n^6 }{ 16m^2n^4*m^3n^6*24m^8n^8 }\]

simplify it from here now :)

Answer 9

ookay. Thanks!

Answer 10

first simplify the numerator using first use these properties to simplify \(\Large a^b\times a^c = a^{b+c}\)

and then the denominator

and then use this formula

\(\Large\frac{a^b}{a^c} = a^{b-c}\)