What function accurately represents the sine curve for orange light?
@mathstudent55
ik the anwser
http://jwilson.coe.uga.edu/EMAT6680Fa09/Gonterman/Gonterman1/Gonterman1.html
The regular sine function y = sin x has period 2pi In this case yo have period 610 nm
y = sin (Bx) has period \(|\dfrac{2 \pi}{B}|\)
Set your specific period equal to the period formula and solve for B.
so pi/610?
\(|\dfrac{2 \pi}{B}| = 610\) \(\dfrac{2 \pi}{B} = 610\) \(2 \pi = 610B\) \(\dfrac{2 \pi}{610} = B\) \(\dfrac{\pi}{305} = B\)
Ohhhhh i got it now that makes sense lol
\(y = \sin Bx\) \(y = \sin \dfrac{\pi}{305}x \)
is my answer right for this
@mathstudent55
Notice first the amplitude. The function goes from -3 to 3. A regular sine or cosine curve goes from -1 to 1. The amplitude is 3 times greater, so there must be a multiplier of 3 to the amplitude.
All choices do have a 3 or -3.
Now let's see what happened to the horizontal position.
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