Here are the golf scores of 12 members of a college women's golf team in two rounds of tournament play. (A golf score is the number of strokes required to complete the course, so that low scores are better.) To what extent may we predict the second round score from the first round score? The standard error of the slope is 0.23. Player 1 2 3 4 5 6 7 8 9 10 11 12 Round 1 89 90 87 95 86 81 102 105 83 88 91 79 Round 2 94 85 89 89 81 76 107 89 87 91 88 80 a. Find a 95% confidence interval for the slope. b. Find a 99% confidence interval for the slope
yes :) @_Malice_
So would this be any kind of help? http://openstudy.com/updates/53e53c15e4b0e7ddacf67719 \
no one gave any helpful advice on that question :/ @_Malice_
welp Sorry, thats as far as my help goes, I'm not useful after that ;-;
This isn't my area of expertise, atleast not these kind of questions
ha, thank you anyways :) @_Malice_
Np :(
@TheSmartOne
how you got the stander error 0.23?
that was just in the question @timamits
i think the problem is very simple, you need to calculate mean of first round score. say that is ybar. then 95% confidence interval will ybar +/- se * 1.96 and 99% confidence interval ybar +/- se * 2.56.
??? @timamits
ybar is the mean of the first round score which will be 89.66. You can not use second round scores to predict second round scores. Now assuming that scores follows a normal distribution with the mean 89.66 and standard deviation 0.23. Then use the formula for 95% confidence interval:- mean +/- (standard deviation* 1.96 and mean +/- (standard deviation* 2.56. Do you have a calculator to calculate points on normal distribution.
The numbers 1.96 and 2.56 are standard values for percentage points on normal distribution.
it will be 2.58 for 99% confidence interval instead of 2.56.
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