Ask your own question, for FREE!
Earth Sciences 8 Online
OpenStudy (mutie):

PLEASE HELP! Please check my answers? I need to determine the density for each model. Here's the table: http://prntscr.com/c745sm My answers... Conglomerate: 226 cm3 Plain: 234 cm3

OpenStudy (mutie):

@sammixboo @Whitemonsterbunny17

OpenStudy (mutie):

Oh wait.. I put in the wrong numbers for my answers hold on

OpenStudy (mutie):

Conglomerate: p = 1.858407079646 g/cm3 Plain: p = 0.97863247863248 g/cm3

whitemonsterbunny17 (whitemonsterbunny17):

So according to the table, to find the density the formula is \(\bf\color{black}{g/cm^3}\). For conglomerate we would take \(\bf\color{black}{420/226}\) For plain, we would take \(\bf\color{black}{229/234}\) Your answers are looking correct, however you should probably round to the nearest hundredth (unless your lesson says otherwise).

whitemonsterbunny17 (whitemonsterbunny17):

Also, instead of "p=", you should probably label it as "d" for "density".

OpenStudy (mutie):

Oh okay, thank you. :)

whitemonsterbunny17 (whitemonsterbunny17):

You're welcome, I'm glad to be of help! Let me know if you need help with anything else. :)

OpenStudy (mutie):

@Whitemonsterbunny17 Hi again! I have an answer for this one but I just want to double check... If I add rocks to a certain amount of liquid water and freeze it, then the melting rate will be ____________________ compared to the melting rate of the plain frozen water under the same conditions. (I have to choose Faster, slower or the same.) I believe it might be... faster?

whitemonsterbunny17 (whitemonsterbunny17):

Well, let's think of the rocks as if they were ice cubes. When you add ice cubes to water, it helps to keep the water cooler for longer. It would be the same with the rocks (the rocks would become cold and stay cold for longer). So, they are asking if the \(\bf\underline{\color{black}{melting~rate}}\) would be faster, slower, or the same. The answer to this would not be faster. Do you know what the correct answer is now? @Mutie

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!