To achieve an octet of valence electrons, an iodine atom will become an ion with what charge? -2 -1 +1 +2 @hartnn @mathstudent55 @TheSmartOne @Jadeishere @Donblue22 @.Sam.
Iodine 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p5
Add 1 electron to make it 5p6
And the ion would be \[I^{-1}\] Because you're adding an electron
@.Sam. You should explain that just a LITTLE more
You're doing great, obviously, but, some people don't know why that's a -1 v. +1
I've explained some of it already on some of his previous posts go check it out
@.Sam. Thank you sooooooooooo much for all your help! I love OpenStudy!
Electron is negative and If you add an electron to an element you will get a negative 1. If you remove an electron from it you will get a plus 1, eg. \(I^{+1}\), vice versa
ok
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