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Mathematics 6 Online
OpenStudy (mukul123):

What does it mean?

OpenStudy (mukul123):

ganeshie8 (ganeshie8):

Hey

OpenStudy (mukul123):

hello again

ganeshie8 (ganeshie8):

What's the r'th term in the expansion of (a+b)^n ?

OpenStudy (mukul123):

It is given by nCr*a^(n-r)*b^r . Right?

ganeshie8 (ganeshie8):

Yes, what's the r'th term in the expansion of (1+x)^n ?

OpenStudy (mukul123):

It would be nCn*1^(n-n)*x^n ( nCn and 1^0 is 1 so it would be x^n).

ganeshie8 (ganeshie8):

Careful, I'm asking about the r'th term

OpenStudy (mukul123):

Oops! nCr*x^r

ganeshie8 (ganeshie8):

Yes, r'th term in the expansion of (1+x)^n is nCr*x^r. What must we replace "r" by to see x^(n-2) ?

OpenStudy (mukul123):

n-2

ganeshie8 (ganeshie8):

Yes, what's the "n-2" th term in the expansion of (1+x)^n ?

OpenStudy (mukul123):

nC(n-2)*x^(n-2)

ganeshie8 (ganeshie8):

Right, so the coefficient of x^(n-2), according to our formula of r'th term is nC(n-2)

ganeshie8 (ganeshie8):

Oh sorry, the exponent is 2n, not n. Let's start over...

OpenStudy (mukul123):

then It would be 2nC(n-2)x^(n-2)

ganeshie8 (ganeshie8):

Perfect! r'th term in the expansion of (1+x)^(2n) is (2n)Cr x^r we get x^(n-2) term if we replace r by n-2 above.

ganeshie8 (ganeshie8):

therefore we want to find the n-2 th term in the expansion of (1+x)^(2n) : (2n)C(n-2)*x^(n-2)

ganeshie8 (ganeshie8):

With me so far ?

OpenStudy (mukul123):

Yes

ganeshie8 (ganeshie8):

simple expand (2n)C(n-2) and we're done

ganeshie8 (ganeshie8):

use the formula nCr = n!/[(n-r)! r!]

OpenStudy (mukul123):

Oh! But in book they have expanded 2nC(n+2).

OpenStudy (mww):

it's the same thing nCr = nC(n-r)

ganeshie8 (ganeshie8):

Ahh right, it must be some printing mistake. Replace 2nC(n+2) by 2nC(n-2) and everything should make sense...

OpenStudy (divyankasc):

Hey! Go at brainly.com! You'll get instant answers!

ganeshie8 (ganeshie8):

ncr = nc(n-r) but we don't want to use it here as rth term and n-r th terms wil have different degrees.

OpenStudy (mukul123):

Also, why did they focused in x^(n-2)?... They could have chosen x^(n-1).

ganeshie8 (ganeshie8):

Good question. This will be answered after we look at the right hand side of the equation iii. Your goal here is to find an expression for C0C2 + C1C3 + C2C4 + ...., right ?

OpenStudy (mww):

what is the full question?

OpenStudy (mukul123):

Got it!! Thanks everyone..

ganeshie8 (ganeshie8):

You will be using this trick a lot in "generating functions" which you may be messing with soon. You get to find the coefficient of a certain term like, x^r, which represents number of ways of doing a particular thing. So it is okay if you don't get 100% of the problem now. You're gonna see more of these later and you will understand them after using this trick in different situations.

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