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OpenStudy (quickstudent):
Is this correct?
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OpenStudy (quickstudent):
question attached
my answer:
3x + 1 = (1/3)x + 9
3x + 1 - 1 = (1/3)x + 9 - 1
3x = (1/3)x + 8
3x - (1/3)x = (1/3)x + 8 - (1/3)x
(8/3)x = 8
(8/3)x/(8/3) = 8/(8/3)
x = 3
[3(3) + 1] + [(1/3)(3) + 9 =
[9 + 1] + [1 + 9] =
10 + 10 =
20
Length of AK = 20
OpenStudy (visarika23):
AK=10
AB=20
jhonyy9 (jhonyy9):
x=3 is right sure
jhonyy9 (jhonyy9):
but in this case when x=3 so AK not is 20 please check it again
jhonyy9 (jhonyy9):
the length of AK = 3x +1 so for x=3 how many will get ?
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OpenStudy (quickstudent):
Oops, that's right, I didn't need to solve for the other equation, just AK. alright, here is my correction:
3x + 1 = (1/3)x + 9
3x + 1 - 1 = (1/3)x + 9 - 1
3x = (1/3)x + 8
3x - (1/3)x = (1/3)x + 8 - (1/3)x
(8/3)x = 8
(8/3)x/(8/3) = 8/(8/3)
x = 3
[3(3) + 1] =
[9 + 1] =
10
Length of AK = 10
jhonyy9 (jhonyy9):
yes this is right,correct now sure
OpenStudy (visarika23):
Now its correct :)
OpenStudy (quickstudent):
Thanks
jhonyy9 (jhonyy9):
my pleasure -
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OpenStudy (visarika23):
☺☺
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