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Mathematics 16 Online
OpenStudy (abbles):

Vectors Q

OpenStudy (abbles):

For a, |v1| = 2sqrt10 |v2| = sqrt65 Right?

OpenStudy (visarika23):

Right

OpenStudy (welshfella):

Yes

OpenStudy (abbles):

For B I was a little unsure... would these be the unit vectors? \[(\frac{ 1 }{ \sqrt10 }, \frac{ 3 }{ \sqrt 10 })\] and \[(\frac{ -4 }{ \sqrt65 }, \frac{ 7 }{ \sqrt65 })\]

OpenStudy (visarika23):

Yes ...but in first one it will be -3/square root10

OpenStudy (visarika23):

Unit vector is just v/|v|

OpenStudy (abbles):

Right! Good catch. What about the graph? I drew a dot at (-4, 7) and another dot at (2, -6)... then a dot at (-2, 1)... I don't know how to draw vectors :P

OpenStudy (visarika23):

Yes u have done right v1 and v2 u can simply plot For v1+v2 u have to do vector addition v1=2i-6j v2=-4i+7j v1 + v2= 2i-4i-6j+7i =-2i+j

OpenStudy (abbles):

Where do the i and the j come from? Wouldn't it just be (-2, 1) for the vector addition? How would I graph all of this?

zepdrix (zepdrix):

Yes, that's just another way of writing vectors,\[\large\rm <-2,1>\quad=\quad -2\hat i+1\hat j\]i is the horizontal unit vector, we have 2 of those going in the left direction. j is the vertical unit vector.

zepdrix (zepdrix):

What are we doing Pebs? Graphing stuff?

OpenStudy (abbles):

Zep, how would I graph these? :)

OpenStudy (abbles):

Yeah, here is the thingy

OpenStudy (abbles):

c

zepdrix (zepdrix):

|dw:1471717901915:dw|

zepdrix (zepdrix):

So umm

OpenStudy (abbles):

A dot a (-4, 7), a dot at (2, -6)... then a dot at (-2, 1)?

zepdrix (zepdrix):

|dw:1471717962689:dw|

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