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how do i solve this (x+3)log4=(x)log9
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distribute the x+3 then collect x terms on one side and non x terms on the other side.
okay let me try
xlog4+3log4=xlog9
right now pull the x to the right side perhaps by subtraction
xlog 4-xlog9=-3log4 x(log3-log9)=-3log4 x=-3log4/log3-log9=5.129
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hmm
looks good assuming you had parenthesis for bottom, let me try with my calc.
okay
I get 3.786
hm
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dont forget its -3log4/(log3-log9)
oops mistake earlier
xlog 4-xlog9=-3log4 x(log3-log9)=-3log4 x=-3log4/log3-log9=5.129
That bit has a mistake
denominator would be log 4-log 9
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Right
5.129
Looks good now
thank you so much for your help. got it
Ok good.
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