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Mathematics 18 Online
OpenStudy (brydenwright):

Express the complex number in trigonometric form. -2

zepdrix (zepdrix):

Here is a good way to get started,\[\large\rm -2\quad=\quad -2+0i\]So what does this tell us? We have no imaginary component, no vertical component. So our value lies on `the real axis`, yes?

OpenStudy (brydenwright):

Would the answer be 2(cos 0° + i sin 0°)? I have 2 for R and the angle as arctan(0).

zepdrix (zepdrix):

Well there's a nice easy way to check your work. Simplify cos0 and sin0. cos 0 = 1 sin 0 = 0 right? So you end up with 2(1+0i) Hmm that doesn't give us the -2 we need :(

zepdrix (zepdrix):

you had arctan(0)? Ok that's good. arctangent will always spit out this principle value in the first or fourth quadrant though. Notice that -2 is along the negative real axis. So it's between quadrants 2 and 3. We can take our angle that we ended up with and add 180 to it. (Because tangent is periodic in 180 degrees).

OpenStudy (brydenwright):

so 2(cos 180° + i sin 180°)?

zepdrix (zepdrix):

Again, check your work. What do you end up with?

zepdrix (zepdrix):

cos180 = ? sin180 = ?

OpenStudy (brydenwright):

2(-1 + 0i) right?

zepdrix (zepdrix):

Ahh it worked out! Nice! :) Yes good job.

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