Question

simplify. write answers with negative exponents.
(abc)^-3 c^2 b
------------
a^-4 bc^2 a

Answer 1

i dont know how to turn this into a negative exponent. can you help me @agent0smith

Answer 2

Simplify it as normal first, then worry about the negative exponents.

Answer 3

i already did it where it say up top that this is the step before last

Answer 4

Completely simplify it. That's not even close.

Answer 5

wait that was the wrong step sorry

Answer 6

Completely simplify it, then move terms to the numerator (or denominator) to make them negative.

If you know how to make a negative exponent into a positive exponent, then you can do the reverse.

Answer 7

\frac{ a ^{-3}b ^{2}c ^{-1}} }{a ^{-3}bc ^{2} }

Answer 8

I can tell that's still not completely simplified...

Answer 9

ac^3/b^-3

Answer 10

is that right or no?

Answer 11

http://www.wolframalpha.com/input/?i=((abc)%5E-3+c%5E2+b)%2F(a%5E-4+bc%5E2+a)

Answer 12

but it is supposed to be negative and were did the a go?

Answer 13

(a) go

Answer 14

The \(a\) canceled out. It's easy to now make them negative.

If you know how to make a negative exponent into a positive exponent, then you can do the reverse of that.

Answer 15

1 / b^-3 c^-3

Answer 16

\[\Large x^{-b} = \frac{ 1 }{ x^b }\]shouldn't be hard to do that in reverse... start from the right side, go back to the left

Answer 17

b^-3 = 1/b^3
c^-3=1/c^3

Answer 18

The question is

(abc)^-3 c^2 b
------------
a^-4 bc^2 a

Lets bring the division as multiplication , so we would get the signs as opposite.

So it becomes (abc)^-3 . c^2 . b . a^4 . b^-1 . c^-2 . a^-1

Further solving we get

a^(-3+4-1) . b^(-3+1-1) . c^(-3+2-2)
= a^0 . b^-3 . c^-3

=1/(b^3.c^3) is the final answer.

simply solve for all the powers of a , b & c individually.