sumone highlight the main things about this topic and the things i need to keep in mind for this topic!! ^.^
also refer me to a youtube video on this topic
Look at the bottom conclusion please :-)
yeah but it doesn't tell me what key points/tricks i need to keep in mind..
Go to youtube and look up "instantaneous rate of change" at the khan academy
no but this involves i lil biff of calcu...
Instantaneous rate of change is linked with calculus
ok abbu
tanks guys, i really appreciated your struggle n effort.. <3
Yaar dekho yaha elaan na karo meri badnaami hogi.
juhahahahahaha......
has raha he dhas raha he?
wodda....dhas?? thats not even a werd abbu meyaan!!
dhasna, yaar nahi pata?
chal bta de...papa!!
@zepdrix i don't get what A(a,f(a) means and idk where "B(a+h,f(a+h))" came from..plz summerize it for me.plz!! X"D
plz tell me the steps.how do i approach to solve these questions....<3
You're probably familiar with labeling points like this, yes? \(\large\rm A(x_1,y_1)\) and \(\large\rm B(x_2,y_2)\)
A is some ordered pair x,y. I put the 1 to show that it's different than the other x,y.
ockay..kinda...i mean yes..that A(x,y), B(x,y)..sure!!
Yes, but we need to show that the x,y in A are different than the x,y in B. So we have to make them different some how. Anyway, now that you're venturing into "big boy math", you have to get comfortable with function notation.
Instead of using \(\large\rm x\) and \(\large\rm y\), we'll be using \(\large\rm x\) and \(\large\rm f(x)\) from now on.
aawwnn ok...keep going
So your ordered pair now looks like this: \(\large\rm A(x,y)=A(x,f(x))\)
All we did was replace y with f(x).
its actually A(a,f(a)) but same thing i guess!! ^.^
Yes, that's the next step. We'll start at some location x=a. \(\large\rm A(a,f(a))\) k cool.
So it has an x coordinate of a, and a y coordinate of f(a).
ok ☺
To get to our next point, we'll add some length h to the starting point. So our new x coordinate will be located at a+h.
The new y coordinate will be the `function of that x coordinate`. f(a+h) <- new y coordinate.
ockay🙂🙂
Do you remember your old fancy slope formula?\[\large\rm m=\frac{y_2-y_1}{x_2-x_1}\]That's exactly what we're doing here, but we're using function notation so it looks unfamiliar.
so the "h" in f(a+h) basically y??
The whole thing f(a+h) is your new y.
o eye c!! ^.^
|dw:1472053997194:dw|it really helps if you can think of these coordinates as `lengths` and `heights` instead of just `points` floating around.
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