Question

The line of symmetry for the quadratic equation y=ax2-8x-3isx=2 what the value of "a"

Answer 1

a=19/4 + y/4
not 100 percent sure tho

Answer 2

y=ax^2 - 8x -3
If line of symmetry is x = 2, then in this line y is always 0.
Which means for x=2 y=0
So substituting y=0 and x=2 in y=ax^2 - 8x -3
we get 0=4a-16-3
4a=19

a=19/4

Answer 3

Medal please... if you found the answer useful...

Answer 4

@niksbhalla14mar it is not correct. How to get the medal?

Answer 5

Solution is correct loser

Answer 6

I prove it is wrong!!
if the answer is 19/4, then the quadratic equation is \(y=\dfrac{19}{4}x^2-8x-3\)
the x-coordinate of th vertex of this parabola is \(x=-\dfrac{b}{2a}=\dfrac{16}{19}\neq 2\)
Note that the line of symmetry for the quadratic must past its x -coordinate of its vertex.
Hence the answer a=19/4 is NOT correct