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Mathematics 7 Online
OpenStudy (erinkb99):

f is a continuous function with a domain [−3, 9] such that (see picture) and let (see picture). On what interval is g increasing? For 0 ≤ x ≤ 6, express g(x) in terms of x.

OpenStudy (erinkb99):

OpenStudy (erinkb99):

OpenStudy (erinkb99):

@zepdrix

zepdrix (zepdrix):

Why separately? XD lol We were almost done :D

zepdrix (zepdrix):

g'(x) = f(x) So when x is between 0 and 6, g'(x) = what?

OpenStudy (erinkb99):

So I could medal you twice!

OpenStudy (erinkb99):

changing from positive to negative?

zepdrix (zepdrix):

Remember g'(x) = f(x). We figured that out. So when x is between 0 and 6, f(x) = ?

OpenStudy (erinkb99):

0?

zepdrix (zepdrix):

f(x) is piece-wise. So it's one of the three pieces when x is between 0 and 6, which one?

OpenStudy (erinkb99):

oh oops -x +3

zepdrix (zepdrix):

k good so when x is between 0 and 6,\[\large\rm f(x)=-x+3=g'(x)\]So there is your answer. Oh wait wait wait.. that's g'(x). They want g(x). Interestingggg

OpenStudy (erinkb99):

-1/2x^2 +3x??

zepdrix (zepdrix):

That's what I was thinking maybe... hmm sneaky sneaky problem -_-

OpenStudy (erinkb99):

Indeed haha

zepdrix (zepdrix):

Hmm I'm a little stumped on this part :C Hope we did that properly.

OpenStudy (erinkb99):

Probably its right. I have one more question thats pretty easy I just think I'm psyching myself out

zepdrix (zepdrix):

XD k let's check it out

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