f is a continuous function with a domain [−3, 9] such that (see picture) and let (see picture). On what interval is g increasing? For 0 ≤ x ≤ 6, express g(x) in terms of x.
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OpenStudy (erinkb99):
OpenStudy (erinkb99):
OpenStudy (erinkb99):
@zepdrix
zepdrix (zepdrix):
Why separately? XD lol
We were almost done :D
zepdrix (zepdrix):
g'(x) = f(x)
So when x is between 0 and 6, g'(x) = what?
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OpenStudy (erinkb99):
So I could medal you twice!
OpenStudy (erinkb99):
changing from positive to negative?
zepdrix (zepdrix):
Remember g'(x) = f(x).
We figured that out.
So when x is between 0 and 6, f(x) = ?
OpenStudy (erinkb99):
0?
zepdrix (zepdrix):
f(x) is piece-wise.
So it's one of the three pieces when x is between 0 and 6,
which one?
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OpenStudy (erinkb99):
oh oops
-x +3
zepdrix (zepdrix):
k good so when x is between 0 and 6,\[\large\rm f(x)=-x+3=g'(x)\]So there is your answer.
Oh wait wait wait.. that's g'(x).
They want g(x). Interestingggg
OpenStudy (erinkb99):
-1/2x^2 +3x??
zepdrix (zepdrix):
That's what I was thinking maybe...
hmm sneaky sneaky problem -_-
OpenStudy (erinkb99):
Indeed haha
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zepdrix (zepdrix):
Hmm I'm a little stumped on this part :C
Hope we did that properly.
OpenStudy (erinkb99):
Probably its right. I have one more question thats pretty easy I just think I'm psyching myself out