If f(x)=7x-5x^2, then find each of the following: A.) f(3k-7) B.) f(x+h) C.) f(-4k^5)
You simply plug in 3k-7 in place of every x and simplify f(x) = 7x - 5x^2 \(f(\color{red}{3k - 7}) = 7(\color{red}{3k-7}) - 5(\color{red}{3k-7})^2\)
Okay that makes sense! Will you check my answers when I'm done?
A I got -14
Sure! :)
We have variables, how did you get rid of them? Can you show your work so I can see where you went wrong? (:
I used my calculator, guess that doesn't work lol. Let me work it out
Okay I'm stumped
to expand (3k-7)^2 use the formula \(\Large (a-b)^2 = a^2 - 2ab + b^2\) and to open up 7(3k-7) use the distributive property which states a(b-c) = ab - ac
and after you expand (3k-7)^2 don't forget to distribute the -5 ;o
I ended up with f(3k-7)= 21k + 76. I feel like that's not right
Do I need to use that formula for 7(2k-7)?
no, you need to use the distributive property for 7(3k-7) psst, it's 3k not 2k and that's not right either can you show your work? :p
I think I'm doing this all wrong :( Okay f(3k-7) = 7(3k-7) -5(3k-7)^2 (3+7)^2 = 3 - 2(3)(-7)-7^2 10^2 = 3 + 42 - 49 100/-4 = -4/-4 -25 -5(-25) = 125 Then 7(3k-7) 21k - 49 -49+125+21k 76 + 21k
"(3+7)^2 = 3 - 2(3)(-7)-7^2" it's 3k -7, and I don't know what formula you're using o.o try this (3k-7)^2 = (3k)^2 - 2(3k)(7) + 7^2 what do you get?
3k^2 - 6x + 35
\((ab)^m = a^mb^m\) so what is \( (3k)^2 = ?\) and you changed k to x and you didn't multiply 2 * 3 and 7 properly and 7^2 is not 35
I thought 3k^2 just stayed like that? My bad in multiplied 7 by -2 :( Here's what I did (3k)^2 - 2(3k)(7) + 7^2 3k^2-6k -14 +49 3k^2 - 6k + 35
7^2 = 7 * 7 = 49 \( (3k)^2 = 3^2k^2 = 9k^2\) and 2(3k)(7) = 42k sooooo (3k-7)^2 = 9k^2 - 42k + 49 do you understand? o:
That makes a lot more sense. So sorry for the confusion, math isn't my strong subject /:
so what is -5(9k^2 - 42k + 49) distribute the -5 an extension of the distributive property a(b - c + d) = ab - ac + ad
-45k^2 + 210 -245?
yesss, but you dropped the k after 210 and what is 7(3k-7) = ?
Oops typo! 7(3k-7) 21k - 49?
yes, now 21k - 49 -45k^2 + 210 -245 = ?? simplify it by adding/subtracting like terms
-45k^2 + 21k -84
oops, my bad 21k - 49 -45k^2 + 210k -245 = ?? I forgot to put the k after 210 ;p
You're good! So -45k^2 + 231k - 294
bingo!
You're amazing! Would I set b up the same way
yes, instead of 3k-7, you would use x + h
So f(x+h) = 7(x+h) - 5(x+8)^2 Start with (x+h)^2 = x^2 - 2(x)(h) + h^2 right?
yep and then distribute the -5
Okay I got -5x^2 - 5h^2 + 10xh
so we have so far 7(x+h) - 5(x+8)^2 7(x + h) -5x^2 - 5h^2 + 10xh now do 7(x + h)
7x + 7h
7x + 7h -5x^2 - 5h^2 + 10xh now simplify (:
Can that be simplified?
The only thing I could think to do would be 24xh -5h^2 - 5x^2
it can't be simplified :b you can't add h + h to make h^2 only h * h = h^2 h + h = 2h but we can't simplify anymore :)
Okay so it stays how it was?
yeah xD
You tricked me lol. So for c do we still use the whole (a-b)^2=a^2-2ab+b^2 thing?
nope, C is much more simpler xD
Okay so 7(-4k^5) = -28k^5. Do the same to the other side?
yeah, but we first have to square it :)
400k^10?
nooo \((-4k^5)^2 = (-4)^2(k^5)^2\) hint: \( (a^b)^c = a^{bc}\)
16 and k^10? Or would it be k^7?
k^10 is correct and then 5 * 16k^10 = ?
80k^10!
So the answer is 480k^10?
we can't add -28k^5 and 80k^10 and not sure how you got 480 o;
Shoot idk where I got 400k^2 from lol. I added that. So 80k^10-28k^5
xD
Thank you so so much for explaining that! Sorry it took so long
It's alright! Have a great day (:
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