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Mathematics 19 Online
OpenStudy (maddyhall15):

Directions: Complete the table and use the result to estimate the limit. The limit as x approaches 4 is (x-4)/(x^2-3x-4) x|3.9|3.99|3.999|4.001|4.01|4.1 f(x)| | | | | | I don't even remember what a limit is or what any of this means so please be thorough in your response. Thanks!!

zepdrix (zepdrix):

Hey Mads! Small typo here, we're taking the limit `of` a function. The limit as x approaches 4 of* (x-4)/(x^2-3x-4)

zepdrix (zepdrix):

Calculator will be helpful here. Here is our function,\[\large\rm f(\color{orangered}{x})=\frac{\color{orangered}{x}-4}{(\color{orangered}{x}^2-3\color{orangered}{x}-4)}\]So what is our result when we plug x=3.9 into the function?\[\large\rm f(\color{orangered}{3.9})=\frac{\color{orangered}{3.9}-4}{(\color{orangered}{3.9}^2-3\color{orangered}{(3.9)}-4)}\]

OpenStudy (maddyhall15):

So I did that differently, just graphed it and then went to those points, although the answers are the same. I'm not sure how I know what the limit is though. Or really what is means. Most definitions really confuse me. All I know is that it's something a something approaches x but I don't get what that actually means.

zepdrix (zepdrix):

Well with each point, our x is getting closer to 4. Your y should be getting closer to some value. That is the limit, the y value.

OpenStudy (maddyhall15):

So the limit would be 0.2?

zepdrix (zepdrix):

Yes.

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