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Mathematics 8 Online
OpenStudy (louis):

According to the simulations, what is the probability that the treatment group's mean is greater than the control group's mean by 12 baskets or more, and what can be concluded regarding this result? Assume a probability of less than 5% is significant. Whole question here: http://imgur.com/a/Q3jH5

OpenStudy (tay1lynn):

12 men and 50 percent?

OpenStudy (louis):

really dont understand this problem

OpenStudy (agent0smith):

First you have to work out the mean, by adding up all the values and dividing by how many there are. To do that, multiply the value in the left table, by the frequency on the right, for all of them. Eg. (-14)*7 + (-12)*18 + (-10)*20 + ... and so on Then, divide that result, by the sum of all the values in the frequency column

OpenStudy (louis):

ok

OpenStudy (louis):

got 32/1000

OpenStudy (agent0smith):

That doesn't look right at all.

OpenStudy (louis):

got 32 on the left side and 1000 on the right side

OpenStudy (agent0smith):

That isn't what I suggested. Go back and re-read it.

OpenStudy (louis):

i multiplied them by the right side and got 32 then added the frequency side and got 1000 if i divide them i get .032

OpenStudy (tay1lynn):

I would help but I have the same thing you did

OpenStudy (louis):

what answer are u getting

OpenStudy (agent0smith):

Actually no yours looks right. Now we gotta try to figure out the probability

OpenStudy (louis):

this whole lesson doesnt make sense

OpenStudy (agent0smith):

It does, I'm just trying to remember how to get the z-score from a table like this. I think we just need to get the standard deviation, then we can use the z-score formula, but getting std dev is tedious.

OpenStudy (agent0smith):

Yeah i think you need to find the std dev https://puserscontentstorage.blob.core.windows.net/userimages/a3c3271c-61c8-4991-b5c8-5fdb4777e651/8abbec95-babd-4c2a-9943-21b81dc7f399image17.png Std dev is each score minus the mean, squared. You could do it like so (the number out front is the frequency) \[\large 7(-14-0.32)^2 + 18(-12-0.32)^2 + 20(-10-0.32)^2 + ...\] Then you can work out the z-score and the probability from that.

OpenStudy (louis):

almost done with this course but these last 4 assignments have me confused

OpenStudy (agent0smith):

\[\large 7(-14-0.32)^2 + 18(-12-0.32)^2 + 20(-10-0.32)^2 + ... \]Don't forget to then divide by 1000, and then square root it, to get std dev.

OpenStudy (louis):

isnt 0.032

OpenStudy (agent0smith):

Sure, whatever it was.

OpenStudy (agent0smith):

I hate questions like this, they're so tedious to calculate everything.

OpenStudy (louis):

28718.976/1000

OpenStudy (agent0smith):

Square root it. Then find the z score with the formula i gave \[\Large z = \frac{ 12 - 0 }{ \sqrt \frac{ 28718.976 }{ 1000 } }\]Then use a z-table to find the probability

OpenStudy (louis):

z-table?

OpenStudy (agent0smith):

Yes, you should be familiar with those...

OpenStudy (louis):

searched it up seen it before

OpenStudy (agent0smith):

z-score looks like 2.24, but that gives a probability of 1.25%... which doesn't match any answer. Great...

OpenStudy (louis):

this problem has me tired

OpenStudy (tay1lynn):

im lost ...

OpenStudy (louis):

do u need the same problem

OpenStudy (tay1lynn):

yea

OpenStudy (louis):

for what

OpenStudy (tay1lynn):

algerbra 1

OpenStudy (louis):

all the problems i need are so hard

OpenStudy (tay1lynn):

I got the other ones I just need this one

OpenStudy (agent0smith):

@Louis I'd probably go with A, just because it's the closest option. I worked out the mean and standard deviation, and got the same values as you.

OpenStudy (louis):

by any chance can u see if u have better luck with this problem http://imgur.com/a/GGQAP

OpenStudy (tay1lynn):

I cant get the question pulled up

OpenStudy (agent0smith):

That one is easier high score is 38, low is -24 \[\large SD = \frac{ 38-(-24) }{ 6 }\]then plug it into\[\large ME = \pm 2 * \frac{ SD }{ \sqrt { N}}\]N is the number of blue dots on the graph, which i don't feel like counting (i think it's 100, since they said the data was rerandomized 100 times)

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