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Given f(x)=1/"absolute value x" with the following: f(2+h) where h>0.
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\[f(x)=1/\left| x \right|\]
I think the answer is f(x)=1/(-2-h)
what is the question?
if \(h>0\) then \(f(h+2)=\dfrac{1}{|h+2|}=\dfrac{1}{h+2}\)
oh whoops i was thinking of it differently, but i guess that's right.
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If we had \(h<-2\) then we would have \(x+2<0\) so \(f(h+2)=\dfrac{1}{h+2}=\dfrac{1}{-(h+2)}=\dfrac{1}{-h-2}=\dfrac{-1}{h+2} \)
so that's the reason behind the answer?
well i got it so thank you
that was the reasoning behind a different answer.
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