Check my answers? :)
Check a and b, I need help with c.
what is this, if i may ask?
Precalc :)
ok ty
Lol, why do you ask?
it'll be easier to help you knowing what im dealing with
stuff like this right?
http://www.themathpage.com/aprecalc/graphs-of-functions.htm Pretty sure this will help... along with this- https://www.sophia.org/tutorials/precalculus-chapter-1-functions-and-their-graphs. It will give you a general idea to see if you are correct or along the lines.
First two pages I already know, third on is giving me a 404 error.. I mostly just wanted to know if I was correct :P
ok well let me give it a whirl and ill tell you.
thanks :)
If you are talking about The (c) then I would like to say you are correct... http://www.mathamazement.com/Lessons/Pre-Calculus/06_Additional-Topics-in-Trigonometry/de-moivres-theorem.html this identified it... Wasn't ultra familiar with that theorem so sorry for any inconvenience...I believe from what I saw though you are correct with the negative after reviewing the method. Would only be a positive had it been an imaginative number I believe.
"A very important application of De Moivre's Theorem is computing nth roots of complex numbers, where n is a posiive integer."
@zepdrix know this any better than i do, ill be open to suggestions, or if you agree let me know.
Who what? What's happening now? Oh this question :O( I was trying to be a jerk face and avoid this one... It has decimaaaaaaaaaaaaaaaaaaaaaaals :'c
fine ill check it out >:c sec
lol if I could do it you can too zep lol, true hero
Zep! :O how dare you!
For 12 a, they want your z written in polar form, I don't think they want it written as an ordered pair though.\[\large\rm z=\sqrt{218}(\cos0.49+i \sin0.49)\]Your values look correct though.
:*O
thx zep, lifesaver... i gtg tho have a nice day
Same with b, your values look correct, but write it as a complex number in polar form,\[\large\rm zw=3\sqrt{218}~cis1.924\]
Have good night... Sarck 0_o
Thank you so much zep <3 I have another fun one for you! :D
For part c, woops! You accidentally divided the radial values backwards.
Oh no D:
But wait... isn't it 2/8?
what?
sqrt(218) was the radial length of your point z, shouldn't that be on top if we're dividing z by w?
13 looks good
14 looks good
15 looks good, although it can be simplified a little bit
Cosine is an even function so cos(-x) = cos(x), Sine is an odd function so sin(-x) = -sin(x) So our thing\[\large\rm \frac{z_1}{z_2}=\frac14\left[\cos\left(-\frac{29\pi}{30}\right)+i \sin \left(-\frac{29\pi}{30}\right)\right]\]can be written as\[\large\rm \frac{z_1}{z_2}=\frac14\left[\cos\left(\frac{29\pi}{30}\right)-i \sin \left(\frac{29\pi}{30}\right)\right]\]
Oh, you're right! (about the dividing the radicals backward on part c of the first page) Would the answer be sqrt218/3(cos(-1.43) + isin(-1.43)) ?
No. You accidentally subtracted the angle from zw from z.
Argggdonnit Hold on.
-1.046?
0.494 - 1.43
Got it. Thank you SO much zep
yay team
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