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What is the equation in point−slope form of the line passing through (−3, −4) and (0, 2)? (y − 8) = 2(x − 3) (y + 3) = −2(x + 4) (y − 2) = −2(x + 4) (y + 4) = 2(x + 3)
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@AloneS @zepdrix
@JoannaBlackwelder @Jaynator495
Step 1: Start from the standard equation of a straight line
\[y-y1=\frac{ y2-y1 }{ x2-x1 }(x2-x1)\]
?? @sshayer
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can you simplify that?
denominator?
2
\[y-(-4)=\frac{ 2-(-4) }{ 0-(-3) }(x-(-3))\]
ok I see.. Im going to say (A)... once it factors out.
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correct?
\[y+4=\frac{ 6 }{ 3 }(x+3)\]
can you simplify it?
y + 4 = 2(x+3).. divide whats on the out of the parin?
i think i got it thanks
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