Log problem: In an amplifier, the power gain P is given by the function:
Pout P = 10log --- Pin 10 = 10log 7/Pin do you know the logarithms properties ,formulas ?
I solved it but I didn't find any of the answer choice, though 3 was the closest.
like for example log a +log b = log a*b
yes
so in this exercise case log 7/Pin = ?
or than you like log a/b = ?
than you see it above i wrote that log a*b = log a +log b
yes
so than log a/b = ?
log a*b = log a +log b so log a/b = log a -log b do you can using it in this your exercise case ?
log7 - log pin?
Pout P = 10log --- Pin 10 = 10log 7/Pin yes so will be 10 = 10(log 7 - log Pin) and now what can you doing in both sides ?
divide both sides by 10 and so what will get ?
1 = log 7 -log Pin yes ?
yes
log in this case what base has ten or two ?
@mathmale help me please in this above wrote question bc. when i ve learned this log was base 2 but in this case/time not is sure that has base 2
@IrishBoy123 do you can clarify this please ? - ty .
We have to solve for x in 1 = log 7 -log x, right?
yes but you need to know this log has base what ?
bc. you need rewriting this 1 in function of this logarithm
If it's base 10 then the answer is 0.7 watt.
so than this will be a right choice ?
1 = log 7 - log x log x = log 7 - log 10 log x = log 7/10 x = 0,7
They don't specify which base.
ok. than i remember it right somtime said me here in OS that log mean base ten but how i said above when i ve learned with 40 years ago this was base 2
hjkhjkhjkhjk do you can writing please the choices ? probably from there we can deducting what may be the base of log
for this stuff, it's usually base 10
Thanks that makes sense
ok. was our pleasure good luck bye bye
Here are the answer choices: a. 0.7 watt b. 1.43 watts c. 3 watts d. 70 watts e. None of the above
ok. this now make sens and will be the choice a. right sure hope you agree it irishboy
ah! we agree a) !! well done chaps :-)
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