Solve: log x− log (2x − 1) = 0

Question

Solve: log x− log (2x − 1) = 0

hjkhjkhjkhjk · Answer

Select one:
a. 10/19
b. No solution
c. 0
d. 1

jhonyy9 · Answer

use formula log a - log b = log a/b

hjkhjkhjkhjk · Answer

This would be base 10, correct?

jhonyy9 · Answer

yes 

but just add to both sides log(2x-1) and so what will get

jhonyy9 · Answer

this is very easy to solve it

mathmale · Answer

Kindly show your work if you want meaningful feedback on it.

mathmale · Answer

No change of base is needed here.  Where did that suggestion come from?

hybrik · Answer

log x -log(2x-1)=0
x-2x-1=0 (i did 10^ (log x)-10^ log(2x-1)=10^ 0)

jhonyy9 · Answer

how you think thi 10^0 = 1 not zero ?

hjkhjkhjkhjk · Answer

I found the answer, thank you.

hybrik · Answer

oh yeah, i forgot i didnt change it, np

mathmale · Answer

Note 1:  "log" implies that the base is 10.  No need to actually write the "10."
Note 2:  "log x− log (2x − 1)" is the difference of two logs; according to the "division rule" for logs, log x− log (2x − 1) = $$\log\frac{  x }{ (2x-1) }$$

mathmale · Answer

Please solve the original problem for x.

Hint:  the log of what number is zero?

jhonyy9 · Answer

@mathmale sorry but my idea may be that 

log x - log (2x-1)= 0 

log x = log (2x-1)

so 

x = 2x-1 

1 = x 

your opinion please ?

jhonyy9 · Answer

ok. hjkhjkhjk ?

choice d. is right sure

jhonyy9 · Answer

this is what you got too :?

jhonyy9 · Answer

@IrishBoy123

jhonyy9 · Answer

@ganeshie8 
@TheSmartOne

irishboy123 · Answer

sure!

think that is the way mm was going