The number of deer in a wildlife preserve is given by the function D(t)=184(1.1)0.5tD(t)=184(1.1)0.5t, where tt is time in years. How long does it take the deer population to triple?
(You may use a calculator for this problem)

Question

The number of deer in a wildlife preserve is given by the function D(t)=184(1.1)0.5tD(t)=184(1.1)0.5t, where tt is time in years. How long does it take the deer population to triple?
(You may use a calculator for this problem)

hjkhjkhjkhjk · Answer

Select one:
a. 20.8 years
b. 23.1 years
c. 24.6 years
d. 32.1 years

joannablackwelder · Answer

Do you have any thoughts on how to start?

hjkhjkhjkhjk · Answer

Sorry, it came out wrong: D(t)=184(1.1)^0.5t

hjkhjkhjkhjk · Answer

I think it's C.

hjkhjkhjkhjk · Answer

I tried plugging in, but it doesn't seem perfect.

joannablackwelder · Answer

How did you plug it in?

joannablackwelder · Answer

I agree that C is close, but I think there is a better answer.

joannablackwelder · Answer

Any other thoughts?

mathmale · Answer

For starters, please indicate exponentiation correctly:

Correct:     D(t)=184(1.1)^(0.5t)

Incorrect:   D(t)=184(1.1)0.5t

mathmale · Answer

"Triple" means that the number of deer is no longer D(t), but 3[D(t)].

Thus, you need to solve 3D(t) =3 [ 184(1.1)^(0.5t) ] for t.