PLEASE HELP! Graph attached below. Please pay no mind to the answers I have listed! They are my estimated guesses! I really don't know how to do it!
Please walk me through!
@mathmale
@kewlgeek555
@jim_thompson5910
Hello. :3 Okay, so I haven't done this in a while, but I'll still help because I think I still remember. If anyone else notices I did something wrong, just let us know. Thanks! Okay, so the graph itself is graph f. Do you understand that?
Yes
Okay, so for the first part, you have to find f(1). Basically, f(x) = the y-value and x obviously equals the x-value. So this means that You are finding the y-value for when x = 1.
Is 2 a reasonable answer?
2 is a reasonable answer. It's hard to tell honestly because the graph only has 0 and 5, but it seems reasonable. I'd say 2.
Now, for the second question; So do you know where f(40) would be at?
I was thinking positive because 40 x would be positive. No?
Correct!
Wait omg wait. I think we might be incorrect actually.
Yeah, we are incorrect. Okay, so remember 40 is the x-value. But remember that the y-values of the graph decrease as you go more to the right of the graph. So as the x-values increase, the y-values decrease. So it would actually be negative. The graph basically explains it once you realize it.
That makes sense
Okay, perfect!
And I have to go. But the last question seems different, but it is exactly the same as the first question. It's just re-worded basically. That should help.
What about for the last one?
I just explained it ^^
Okay
I got 0 . Can anyone confirm????
This question is unfair because they failed the label the axis properly. Anyways, draw a horizontal line through y = 2 and see where it crosses the graph. If f(0) = 2, then x = 0 is one of the x values. There will be two other x values
-2 and 1??
oh wait, nvm, you said f(1) = 2. I misread
If f(1) = 2 is correct, then x = 1 would be one of the x values
no f(x)=2
I see they have this covered, ask me if you need any help!
no f(x)=2
It's impossible to tell really without accurate labels/numbers on the axis. But if f(1) = 2 is true and this point is at the peak, then x = 1 is one of the x values. Draw a horizontal line from this peak point until you hit the graph again. Where is this other point? This point would be (x,2) where x is some negative number
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