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Mathematics 10 Online
OpenStudy (blondie_b23):

PLEASE HELP! Graph attached below. Please pay no mind to the answers I have listed! They are my estimated guesses! I really don't know how to do it!

OpenStudy (blondie_b23):

OpenStudy (blondie_b23):

Please walk me through!

OpenStudy (blondie_b23):

@mathmale

OpenStudy (blondie_b23):

@kewlgeek555

OpenStudy (blondie_b23):

@jim_thompson5910

OpenStudy (kewlgeek555):

Hello. :3 Okay, so I haven't done this in a while, but I'll still help because I think I still remember. If anyone else notices I did something wrong, just let us know. Thanks! Okay, so the graph itself is graph f. Do you understand that?

OpenStudy (blondie_b23):

Yes

OpenStudy (kewlgeek555):

Okay, so for the first part, you have to find f(1). Basically, f(x) = the y-value and x obviously equals the x-value. So this means that You are finding the y-value for when x = 1.

OpenStudy (blondie_b23):

Is 2 a reasonable answer?

OpenStudy (kewlgeek555):

2 is a reasonable answer. It's hard to tell honestly because the graph only has 0 and 5, but it seems reasonable. I'd say 2.

OpenStudy (kewlgeek555):

Now, for the second question; So do you know where f(40) would be at?

OpenStudy (blondie_b23):

I was thinking positive because 40 x would be positive. No?

OpenStudy (kewlgeek555):

Correct!

OpenStudy (kewlgeek555):

Wait omg wait. I think we might be incorrect actually.

OpenStudy (kewlgeek555):

Yeah, we are incorrect. Okay, so remember 40 is the x-value. But remember that the y-values of the graph decrease as you go more to the right of the graph. So as the x-values increase, the y-values decrease. So it would actually be negative. The graph basically explains it once you realize it.

OpenStudy (blondie_b23):

That makes sense

OpenStudy (kewlgeek555):

Okay, perfect!

OpenStudy (kewlgeek555):

And I have to go. But the last question seems different, but it is exactly the same as the first question. It's just re-worded basically. That should help.

OpenStudy (blondie_b23):

What about for the last one?

OpenStudy (kewlgeek555):

I just explained it ^^

OpenStudy (blondie_b23):

Okay

OpenStudy (blondie_b23):

I got 0 . Can anyone confirm????

jimthompson5910 (jim_thompson5910):

This question is unfair because they failed the label the axis properly. Anyways, draw a horizontal line through y = 2 and see where it crosses the graph. If f(0) = 2, then x = 0 is one of the x values. There will be two other x values

OpenStudy (blondie_b23):

-2 and 1??

jimthompson5910 (jim_thompson5910):

oh wait, nvm, you said f(1) = 2. I misread

jimthompson5910 (jim_thompson5910):

If f(1) = 2 is correct, then x = 1 would be one of the x values

OpenStudy (blondie_b23):

no f(x)=2

OpenStudy (helpppp):

I see they have this covered, ask me if you need any help!

OpenStudy (blondie_b23):

no f(x)=2

jimthompson5910 (jim_thompson5910):

It's impossible to tell really without accurate labels/numbers on the axis. But if f(1) = 2 is true and this point is at the peak, then x = 1 is one of the x values. Draw a horizontal line from this peak point until you hit the graph again. Where is this other point? This point would be (x,2) where x is some negative number

jimthompson5910 (jim_thompson5910):

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jimthompson5910 (jim_thompson5910):

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jimthompson5910 (jim_thompson5910):

|dw:1472527052434:dw|

jimthompson5910 (jim_thompson5910):

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