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OpenStudy (iwanttogotostanford):
@mathstudent55 @retirEEd @welshfella
OpenStudy (iwanttogotostanford):
@zepdrix @imqwerty
OpenStudy (iwanttogotostanford):
@Sheraz12345
OpenStudy (mathstudent55):
The -3 changes the amplitude of the function, not the period, so the period of the given function is the same as the period of the base function \(y = \cos x\)
OpenStudy (iwanttogotostanford):
its 2pi I've got it never mind
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OpenStudy (iwanttogotostanford):
can i still have help with another though?
OpenStudy (mathstudent55):
correct
OpenStudy (iwanttogotostanford):
not sure about this one^
OpenStudy (mathstudent55):
I have to go, but I'll be back in 15 min.
OpenStudy (iwanttogotostanford):
oh ok thank!
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OpenStudy (mathstudent55):
Very quickly.
A polynomial function with zeros "a", "b" and "c" is
y = (x - a)(x - b)(x - c)
Replace a, b, and c with your zeros and multiply it out.
OpenStudy (mathstudent55):
Notice the form is x - a, x - b, x - c.
Be careful with the signs.
OpenStudy (mathstudent55):
gtg
will be back soon
OpenStudy (iwanttogotostanford):
ok thanks!
OpenStudy (iwanttogotostanford):
anyone help?
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OpenStudy (mathstudent55):
I'm back
OpenStudy (mathstudent55):
Didn't you understand my explanation?
OpenStudy (mathstudent55):
Start with
\(y =(x - \color{red}{a})(x - \color{red}{b})(x - \color{red}c) \)
Now replace a, b, and c with the given zeros.
\(y = (x - \color{red}{6})(x - \color{red}{(-5)})(x - \color{red}2)\)
Now simplify the double negative of the middle factor.
Then multiply the three binomials together.