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Mathematics 16 Online
OpenStudy (iwanttogotostanford):

ple

OpenStudy (iwanttogotostanford):

@mathstudent55 @retirEEd @welshfella

OpenStudy (iwanttogotostanford):

@zepdrix @imqwerty

OpenStudy (iwanttogotostanford):

@Sheraz12345

OpenStudy (mathstudent55):

The -3 changes the amplitude of the function, not the period, so the period of the given function is the same as the period of the base function \(y = \cos x\)

OpenStudy (iwanttogotostanford):

its 2pi I've got it never mind

OpenStudy (iwanttogotostanford):

can i still have help with another though?

OpenStudy (mathstudent55):

correct

OpenStudy (iwanttogotostanford):

not sure about this one^

OpenStudy (mathstudent55):

I have to go, but I'll be back in 15 min.

OpenStudy (iwanttogotostanford):

oh ok thank!

OpenStudy (mathstudent55):

Very quickly. A polynomial function with zeros "a", "b" and "c" is y = (x - a)(x - b)(x - c) Replace a, b, and c with your zeros and multiply it out.

OpenStudy (mathstudent55):

Notice the form is x - a, x - b, x - c. Be careful with the signs.

OpenStudy (mathstudent55):

gtg will be back soon

OpenStudy (iwanttogotostanford):

ok thanks!

OpenStudy (iwanttogotostanford):

anyone help?

OpenStudy (mathstudent55):

I'm back

OpenStudy (mathstudent55):

Didn't you understand my explanation?

OpenStudy (mathstudent55):

Start with \(y =(x - \color{red}{a})(x - \color{red}{b})(x - \color{red}c) \) Now replace a, b, and c with the given zeros. \(y = (x - \color{red}{6})(x - \color{red}{(-5)})(x - \color{red}2)\) Now simplify the double negative of the middle factor. Then multiply the three binomials together.

OpenStudy (yumyum247):

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