ple
@mathstudent55 @retirEEd @welshfella
@zepdrix @imqwerty
@Sheraz12345
The -3 changes the amplitude of the function, not the period, so the period of the given function is the same as the period of the base function \(y = \cos x\)
its 2pi I've got it never mind
can i still have help with another though?
correct
not sure about this one^
I have to go, but I'll be back in 15 min.
oh ok thank!
Very quickly. A polynomial function with zeros "a", "b" and "c" is y = (x - a)(x - b)(x - c) Replace a, b, and c with your zeros and multiply it out.
Notice the form is x - a, x - b, x - c. Be careful with the signs.
gtg will be back soon
ok thanks!
anyone help?
I'm back
Didn't you understand my explanation?
Start with \(y =(x - \color{red}{a})(x - \color{red}{b})(x - \color{red}c) \) Now replace a, b, and c with the given zeros. \(y = (x - \color{red}{6})(x - \color{red}{(-5)})(x - \color{red}2)\) Now simplify the double negative of the middle factor. Then multiply the three binomials together.
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